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Old 09-15-2011, 04:55 PM   #1
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Conversion in the number of shape changes create graphics


Rabbits, the full amount will be increased (4-2 =) 2 (only). Therefore need to be replaced free of only a few chickens (ie, only the number of rabbits) is (2O ÷ 2 =) lO (only), then the chickens (4o-lO =) 30 (only). Solution two heads are assumed 4o rabbit, then there should be enough (4 × 40 =) 160 (only), more than the actual (160-100 =) 60 (only) so you need to be part of the rabbit for the chicken: and put a rabbits into a chicken, the full amount will be reduced (4-2 =) 2 (only). Hence the need to replace the chicken only a few rabbits (ie, chicken-only number) is (60 ÷ 2 =) 30 (only), then there are rabbits (40-30 =) lO (only). This is the assumption that exchange between two objects, with the formulas can be summarized as follows: two things as a thing to be, assuming that the actual comparison. Problems in the relationship according to calculation, the difference is large or small. First set a try and calculate the difference by how much. Then once included in addition to, and ultimately determine how much change. Second, by the A thing of two things (two things of which an equal number) of the bundle assuming replacement. Example 2 games badminton games sold a 40 yuan, 30 yuan, 5O million tickets were 4OO sheets, income 15,600 yuan,Beats By Dre Headphones, which 4O 5O million yuan and the number of sheets of votes equal. How many of each ticket sold for each? Solutions assume that 4OO tickets are 3O yuan each, the income is (30 × 400 =) 12000 (RMB), less than the actual animal husbandry into (15600-12000 =) 3600 (Yuan ). This will require a portion of 30 yuan a ticket into 40 yuan each, or 50 yuan each. Because 40 and $ 5O per ticket equal to the number of sheets, so for a $ 40, it is necessary also for a 5O dollars. That is, one need to replace two tickets for $ 30 a 4o dollars and a $ 50, while revenues will increase for a (40 +5 O a 30 × 2 =) 30 (million). Therefore needs to be replaced (3600 ÷ 30 =) 120 (times), that 4o 5O million yuan each, and each ticket is a (1 × 120 =) 120 (sheets), then 3O dollars a ticket is ( 400-120 × 2:) 16o (Zhang). 2. A thing of two things (of which there are times things than relations) times more than the assumed replacement. Example 3 with A, B, C three kinds of exercise books, prices are 70 cents, 30 cents and 20 cents. Three kinds of exercise books and bought a total of 47, paid $ 1.2 2l, B to buy the number of exercise books exercise books is gamma 2 times. Three kinds of exercise books of how much to buy this? Solution of $ l2 2l angle: 212 angle. Suppose that 47 is a kind of exercise books. Cope (7X47 =) 329 (corner), than the actual pay (329-212 =) ll7 (angle). This kind of practice need to be part of the book into a B or C types of exercise books exercise books. B because the number of exercise books exercise books is gamma 2 times, so for a gamma exercise books, while some properties will, by means of the number of measurement and analysis, to be precise technology. (4) as shown in Figure 4, the shaded area is a triangle, and the high end is not easy to solve. But relatively easy to find a blank part of the area. So there, Figure 4l0 × 10 +6 × 6 one (10 +6) × 10 ÷ 2 a (10-6) × 10 ÷ 2-6 × 6 ÷ 2:1 oo +36-8 O a 2O-l8 = 36 - 18 = 18 Similarly,tods shoes outlet, we reflect on the above calculation. Not difficult to find two large square area of ​​the triangle area and offset, the result is a small square area of ​​the half. Then this process is reflected in the graph look like? Has the geometric interpretation of it? In fact, we as a secondary line, is not difficult according to the nature of the ladder,######## oakley sunglasses, that big square in the shaded area is equal to ① the small square in the lower left ② the area of ​​the triangle side, so that is a small square shaded half of the area. So we found a large square of side length this condition is not required to know, just know that little square of side length can be. If only given a small square side length, the greatly increased difficulty of the subject. In short,diesel store paris, some graphics directly into the subject encounter difficulties, we can make use of the process of derivation of algebraic calculations, the number thought to form, shape and number by finding the relationship between the conversion in the two to create the in order to find different ideas into graphics, so simple solution, from which raise new issues. Good penetration to help shape the number,Oakley sunglasses sale, the number of help-shaped, Shuxingjiege mathematical ideas. A 27 a More articles related to topics:


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