1, ten by ten : -
formulas : the head by head , tail plus tail, tail by tail . -
Example : 12 × 14 =? -
solution : 1 × 1 = 1 -
2 +4 = 6 -
2 × 4 = 8 -
12 × 14 = 168 -
Note: a bit multiply, not to use the 0 digit placeholder . -
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2. head the same ,
GHD Diamond Flag 2011, complementary tail (tail sum equal to 10 ):-
formulas: a first add 1 to the head by head , tail by tail . -
Example : 23 × 27 =? -
solution : 2 +1 = 3 -
2 × 3 = 6 -
3 × 7 = 21 -
23 × 27 = 621 -
Note: a bit amplify, no to use the 0 numeral placeholder . -
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3, the first multiplier complementary , the same for distinct multiplier : -
formulas: a 1st increase 1 to the head by head ,
GHD Classic Straighteners, tail by tail . -
Example : 37 × 44 =? -
solution : 3 +1 = 4 -
4 × 4 = 16 -
7 × 4 = 28 -
37 × 44 = 1628 -
Note: a bit multiply, not to use the 0 digit placeholder . -
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4, dozens of dozens of 1 by one : -
formulas : the brain at head ,
GHD Purple Straighteners, head and head,
GHD Red Straighteners, tail at tail . -
Example : 21 × 41 =? -
solution : 2 × 4 = 8 -
2 +4 = 6 -
1 × 1 = 1 -
21 × 41 = 861 -
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5,11 by any number : -
formulas : the whereabouts of the nailed end to end , in the medium of the drop-down. -
Example : 11 × 23125 =? -
solution : 2 +3 = 5 -
3 +1 = 4 -
1 +2 = 3 -
2 +5 = 7 -
2 and 5 , respectively, in the end to end -
11 × 23125 = 254375 -
Note : and over 10 to enter one . -
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6,
GHD IV Dark Straighteners, a dozen by any number : -
formulas : the whereabouts of the second activity is not the first multiplier , multiplying the first element a bit back the second factor of every number , plus the afterward digit ,
GHD MK4 Gold Straighteners, anew falling . -
Example : 13 × 326 =? -
solution : 13 bits namely 3 -
3 × 3 +2 = 11 -
3 × 2 +6 = 12 -
3 × 6 = 18 -
13 × 326 = 4238 -
Note : and over 10 to enter one . -