Three words of the word, worthwhile of accumulatio

three Jinnian Xin (xīn) c a water study Miao (miǎo) read the three launch Yan (yàn) read the three soils (yáo)
read three cattle (bēn) three hands read (pá) read the three projects (mò) three field study (lěi )
three horses read (biāo) read the three sheep (shān) read the three dogs (biāo) three deer study (cū)
three fish study (xiān) read the three beta (bì) read the three forces (prevaricate) read three vellus cilia (cuì)
; Three ear read (niè) three cars read (hōng) read three straight chu (chù) read the three dragons (tà, dá)
Three of the original conception (yuán) three mine-read (bìng) three fly peruse (fēi) read three knives (lí)
; three and read (ruò) three persons read (zhuàng) three small read (mó) three sub-concepts (zhuǎn)
; three only read (sè) three air read (xiū) ; three Falcon read (zá) three Kyrgyzstan read (zhé)
Three words read (tà) read the three tongue (qì) Three Hong Nian (xīn) Sangequan read (xún)
Three mind (suǒ) read the three pearly (xiǎo)
primary to junior high school numbers all formulas


1, each number × total number of shares = ; total ÷ number = number of copies of each
÷ total number of shares = each
2, 1 × multiple times = number of times the digit of ÷ 1 times multiple = multiple
times the number of times = 1 ÷ multiple
3, speed × time = distance speed = distance ÷ time
time = distance ÷ speed
4, unit price × quantity = total ; unit price = total ÷ number
÷ total number = unit price

5, the efficiency of the total work × hours = volume
÷ efficiency = total work hours
÷ total hours of go efficiency
= ; 6, addend + addend = and, and - variant one addend = addend
; 7, minuend - subtrahend = difference minuend - subtrahend = difference ;
subtrahend = difference +
minuend
8, factor × ÷ Factor = Product product = Another factor
a ingredient 9, dividend ÷ divisor = affair = Business dividend ÷ divisor
provider × divisor = dividend


Primary School mathematical formula graphics

1, square: C perimeter space of ​​a side perimeter S = side × 4C = 4a
area = side × side length S = a × a
2, cube: V: Volume a: surface area = edge long edge long edge long × × 6
S table = a × a × 6
Volume = length × edge × edge long edge long V = a × a × a
3,GHD IV Black Straighteners, rectangular:
C perimeter area of ​​a side length S ; perimeter = (length + width) × 2 C = 2 (a + b)
area = length × width S = ab
4, rectangular
V: Volume s: size a: Long b: W h: high
; (1) surface area (length × width × height + length + width × height) × 2 S = 2 (ab + ah + bh)
(2) Volume = length × length × altitude V = abh
5, an area of ​​a triangle
s high end of h area = base × height ÷ 2 s = ah ÷ 2
triangle = area × 2 ÷ high end
; triangle = area × 2 ÷ the end of high
6, parallelogram: s area of ​​a high-end h ; area = base × height s = ah
7, Ladder: s area of ​​a base b on the h following the end of the lofty
area = (base + down on the bottom) × high ÷ 2 s = (a + b) × h ÷ 2
; 8 round: S surface perimeter Π d = diameter of C r = radius
(1) circumference = diameter × Π = 2 × Π × radius ; C = Πd = 2Πr
(2) area = radius × radius × Π
; 9, cylinders: v volume h: high-s: basal area
r: radius of the bottom c: bottom perimeter
; (1) side of the area = circumference × height bottom
(2) area = side area + base area × 2
(3) Volume = base area × height
(4) volume = side area ÷ 2 × radius
10,GHD Benefit Straighteners, a cone: v s bottom area of ​​the high volume of h
r the radius of the bottom volume = base area × height ÷ 3


÷ total number of shares =
average

and differential equation problems

(and + penniless) ÷ 2 = large Number
(and - aggravate) ÷ 2 = decimal

and times of problems
and ÷ (factor -1) = decimal
; decimal × multiplier = large numbers
(or with - decimal = large mathematics)

distinction times the difference among the publish

÷ (multiples -1) = decimal
; decimal × multiplier = large numbers
(or decimal + SD = large numbers)

planting questions
1, non-closure of the cardinal line of the tree planting issue can be divided into the following three cases:
⑴ If both ends of the line of non-closed tree-planting, then:
; number of trees = number of segments + 1 = length ÷ spacing -1
; length = spacing × (number of vegetation -1)
spacing = length ÷ (number of plant -1)
; ⑵ If the non-closed end of the line to plant trees,GHD NZ, not planted the other end, then:
number of trees = number of segments = length ÷ spacing = spacing × number of trees
full
spacing = length ÷ number of trees
⑶ If both ends of the non-closed circle Do not plant trees, then:
number of trees = number of segments -1 = length ÷ spacing -1
length = spacing × (NUMBER +1)
spacing = length ÷ (NUMBER +1)

2, tree planting on the closed circuit between the number of issues are
number of trees = number of segments = length ÷ spacing = spacing × number of trees
full
spacing = length ÷ number of trees

profit and loss issues
(profit + loss) ÷ volume of distribution of the difference between the two = participate in the distribution of shares
(large additional - a small profit) ÷ = ​​twice the difference between the amount allocated to participate in the distribution of copies
(burned - a small wastage) ÷ = ​​twice the difference between the quantity allocated to partake in the delivery of shares

encounter problems
meet the speed and distance = time × met
meet time = distance ÷ speed and
encounter the speed and distance ÷ = encounter meet Time

catch problems
distance = speed chase and chase and the time difference ×
; retrieval and time = distance ÷ speed chase and the velocity difference = difference
chase and pursue and the distance ÷ time

downstream water problems

hydrostatic speed + speed = flow velocity
hydrostatic upstream speed = speed - the speed
hydrostatic flow velocity = (speed + upstream downstream speed) ÷ 2
flow rate = (downstream speed - upwards speed) ÷ 2

the weight of the solute concentration problems
+ solvent = solution of the weight of the weight
÷ solution of the weight of the solute weight concentration × 100% = weight × concentration solution
= weight of solute ÷
concentration of solute = solution of the weight of the weight of

profit and discounts
profit = selling price - cost
margin = Profit ÷ Cost × 100% = (selling amount ÷ price -1) × 100%
; Change Change amount = principal × the percentage of the actual selling price = ÷
deduct the elemental price × 100% (off <1)
Interest = principal × rate × time
after-tax interest = headmaster × rate × time × (1-20%)

length unit conversion
1 km = 1000 meters 1 meter = 10 decimeters
1 decimeter = 10 cm 1 m = 100 cm
; 1 cm = 10 mm

area unit conversion
1 square kilometer = 100 hectares
; 1 hectare = 10,000 square meters
1 square meter = 100 square decimetres
; 1 square decimeter = 100 square centimeters
1 平方 cm = 100 mm

body (content) product unit conversion
1 cubic meter = 1000
1 cubic decimetre cubic decimeter = 1000 cubic centimeters
1 cubic decimeter = 1 liter
1 立方厘米 = 1 ml
1 cubic meter = 1000 liters

Weight unit conversion

1 ton = 1000 kg
; 1 kg = 1000 grams = 1 kg
1 千克

RMB unit transition
1 dollar = 10 angle
; an angle = 10
1 dollar = 100 cents

time unit conversion
1 centenary = 100 years 1 year = December
huge month (31 days) are: 1 3 5 7 8 10 December
Satsuki (30 days) were: 4 6 9 November
; average annual on February 28 days, a leap year on February 29 天
-average 365 days a year ;
1 leap year days = 366 days 1 hour 24 hours
1 min = 60 minutes 60 seconds = 1 hour = 3600 seconds

Primary Mathematics geometry perimeter area volume formula

1, the rectangular perimeter = (length + width) × 2 C = (a + b) × 2
; 2, the perimeter of the square side length × 4 = ; C = 4a
3, the rectangle area = length × width ; S = ab
4, area = side of square length × side length S = aa = a
5,GHD Blue Butterfly 2011, the triangle area = base × height ÷ 2 S = ah ÷ 2
6, the area of ​​parallelogram = bottom × height ; S = ah
7, trapezoid area = (base + down on the bottom) × high ÷ 2 ; S = (a + b) h ÷ 2
8, diameter = radius × 2 d = 2r ; Radius = diameter ÷ 2 r = d ÷ 2
9, circuit of a circle = pi × pi × diameter = radius × 2 c = πd = 2πr
10, circle area = pi × radius × radius

general algebraic formula

1 junior high school had two points and only a straight line
; 2, the shortest line between two points with the angle or isometric
3 of the supplementary angle equal
4, the complementary angle with the same angle or isometric
5 and merely a little over a straight line and understood straight line perpendicular to
6 point outside the points interlocked with straight line segments in always, the shortest vertical segment
7 point outside a straight line via the parallel axiom,
and only a straight line parallel with this line if two lines are
8 and a third line parallel to the two lines are parallel to each other
9 Tong Weijiao equal, the two straight lines parallel to the
; 10 to the switch angles equal, two lines parallel to the
11 complementary with the adjacent angles, two straight lines parallel to the
; 12,GHD MK4 Kiss Straighteners, two parallel lines, Tong Weijiao equal
13 two parallel lines, alternate angles are equal among the two
14 straight line parallel with the side interior angles theorem of complementary
15 ashore either sides of the triangle is greater than the third side
16 inference on both sides of the triangle is fewer than the third side
17 angles of a triangle and the 3 angles of a triangle theorems and is equal to 180 °
; 18, Corollary 1, each triangle of the two acute angles of extra than
19 Corollary 2 one exterior angle of a triangle is equal to and It is no two contiguous internal angles
20 Corollary 3 the triangle exterior angle is greater than any one and it is not adjacent interior angle
21, the corresponding sides congruent triangles, corresponding angles are equal
22 corner edge axiom (SAS)
both sides and their angles are equal to the corresponding two triangles congruent angle edge axiom
23 (ASA)
direcotry with two horns and their corresponding equal sides
two triangles congruent 24 Corollary (AAS)
had two loudspeakers and one corner of the same on the opposite side of the two triangles congruent corresponding
25 Collage justice side (SSS) with the corresponding three sides of equal triangles congruent
26 hypotenuse of two right-angled edge of axioms (HL)
beveled edge and a right-angle equal to the corresponding two triangles congruent
27 Theorem 1 In the angle bisector of a point to distance both sides of this angle is equal
28 Theorem 2-1 the same distance on both sides of corner points, in this corner bisector
29 angle to the angle bisector is equidistant from all points on both sides of the set of
the nature of the isosceles triangle isosceles triangle theorem of 30 two bottom corners are equal
(the other side of the equiangular)
31 Corollary 1 angle of the bisector of an isosceles triangle split the bottom and perpendicular to the bottom of the
32 isosceles triangle the angle bisector, the bottom edge of the middle and the bottom edge of the high overlap with each other
33 Corollary 3 corners of an equilateral triangle are equal, and each angle is equal to 60 °
; 34 decision theorem of isosceles triangle has two angles of a triangle if equal,
then the two angles on the sides of the equal (equiangular, equilateral)
35 inference 1 three angles are equal is equilateral triangle
36 Corollary 2 has an angle equal to 60 ° of the isosceles triangle is equilateral
37 In a right triangle, if one keen angle is equal to 30 °
then it is equal to the hypotenuse of a right-angle side of half
38 navel on the hypotenuse of a right triangle hypotenuse is equal to half the
39 Theorem on the axis line segment point and the two ends of this segment are equidistant
; 40 inverse and a line equidistant from the two end points,
in this segment of the vertical split line
41 perpendicular bisector of line segment and the segment tin be regarded for equidistant from two end points of the set of all points of Theorem 1
42 symmetrical almost a straight line fashion
two graphs are congruent 43 Theorem 2 If two graphics on a straight-line symmetry,
then connecting corresponding points of the axis of symmetry is the perpendicular bisector theorem 3
44 on two graphics symmetry of a straight line,
if their corresponding intersection line or enhancement cable, then the crossing of the inverse of the axis of symmetry
45 ; if the two corresponding points in the connection plot is a straight line with the vertical,
then the two graphics on this line symmetry
46 Pythagorean Theorem the two right-angle triangle edge a, b of the square and,
equal to the square of the hypotenuse c, ie a ^ 2 + b ^ 2 = c ^ 2
47 The converse of the Pythagorean Theorem
If the triangle triangular
long a, b, c has a relationship a ^ 2 + b ^ 2 = c ^ 2,
then the triangle is right triangle

48 Theorem quadrilateral is equal to 360 °
angles 49 quadrilateral exterior angle is equal to 360 °
50 side polygon-shaped angles and theorems of angles n and is equal to (n-2) × 180 °
51 deduction equal to any multilateral exterior angle and 360 °
52 nature of Theorem 1 parallelogram the diagonal of the parallelogram is equal
53 parallelogram parallelogram nature of Theorem 2 on the opposite side equal
54 inference caught in between two parallel lines parallel to line the nature of equal
55 parallelogram parallelogram's diagonal theorem 3 to each other equally
decision theorem parallelogram 56 1
two groups were equal to the diagonal of the quadrilateral is a parallelogram parallelogram
57 decision theorem 2
two groups were equal on the side of a quadrilateral is a parallelogram parallelogram decision theorem
58 3
diagonal split each quadrilateral is a parallelogram parallelogram decision theorem
59 4
a set of edges parallel to the quadrilateral is a parallelogram equal rectangular nature of Theorem 1
60 the four corners of the rectangle are right angles
61 rectangular nature of Theorem 2 ; the diagonal of the rectangle is equal
62 has three rectangular determine angle of Theorem 1 right angles to the rectangular quadrilateral is a rectangle
63 Theorem 2 to determine the diagonal of the parallelogram is a rectangle equal to
64 diamond-shaped nature of Theorem 1, the four sides are equal diamond
65 diamond-shaped diamond of diagonal ecology of Theorem 2, perpendicular to each other,
and split each set of diagonal diagonal diagonal
66 diamond-shaped area = product of half, or S = (a × b) ÷ 2
67 diamond-shaped sides are equal Theorem 1 determine a quadrilateral is a rhombus
; 68 Diamond Theorem 2 apt make sure the diagonal of the parallelogram are perpendicular to every additional diamond
69 square nature of Theorem 1 the four corners of a square are right angles, four sides are equal
70 square nature of Theorem 2, equal to the square of the two diagonals ,
and perpendicular to each other equally, and each diagonal split a set of Theorem 1 on the corner
71 centrosymmetric two graphics are congruent
72 Theorem 2 on the megalopolis of symmetry of the two graphics,
symmetry point connections have been the center of symmetry and is split
73 inverse symmetry ; if the corresponding point of linkage of two graphics have been some point,
and is it equally, then the two graphics on this isosceles symmetry
74 Theorem isosceles trapezoid trapezoidal nature of the end of the two at the same angle isosceles trapezoid are equal
75
the two diagonals are equal 76 isosceles trapezoid decision theorem
in the same two corners on the bottom of the ladder are equal isosceles trapezoid
77 is equal to the diagonal The trapezoid is isosceles trapezoid
78 equal parts parallel segments Theorem
If a set of parallel lines cut in a straight line segment was the same,
then the other straight line intercepted the line are equal
79 Corollary 1, the midpoint of the waist through the ladder and by the end of a parallel line, the other will be shared equally at the waist
80 Corollary 2 side of the midpoint of the triangle parallel with the other side of the line,
ambition split the third side
81 Theorem triangle median line of the triangle parallel to the median line the third side,
and equal to half of it
82 trapezoid trapezoid theorem of the median line centre line parallel to the two at the end,
and equal to the bottom and two
half
; L = (a + b) ÷ 2 S = L × h
83 (1) the proportion of the elementary properties
If a: b = c: d, then ad = bc if ad = bc,
then a: b = c: d
84 (2) the nature of cooperation than if a / b = c / d, then (a ± b) / b = (c ± d) / d
85 (3) If the geometric properties of a / b = c / d = ... = m / n (b + d + ... + n ≠ 0),
then (a + c + ... + m) / (b + d + ... + n) = a / b
86 parallel line segments proportional to the theorem of three sub-parallel lines hack two lines,
from the corresponding proportion
87 segment inference straight line parallel to the cut-off the other side of the triangle on both sides
(or both sides of the extension cord), which is proportional to
88 should line if a straight line cut Theorem both sides of a triangle
(or both sides of the extension cord) from the corresponding line segments proportional,
then this line parallel to the triangle's third side
89 parallel to the side of the triangle,GHD Deluxe Midnight 2011, and, and straight line intersecting the other side,